170=42x^2

Solution for 170=42x^2 equation:

170=42x^2

We move all terms to the left:

170-(42x^2)=0

a = -42; b = 0; c = +170;
Δ = b2-4ac
Δ = 02-4·(-42)·170
Δ = 28560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28560}=\sqrt{16*1785}=\sqrt{16}*\sqrt{1785}=4\sqrt{1785}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{1785}}{2*-42}=\frac{0-4\sqrt{1785}}{-84}
=-\frac{4\sqrt{1785}}{-84}
=-\frac{\sqrt{1785}}{-21}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{1785}}{2*-42}=\frac{0+4\sqrt{1785}}{-84}
=\frac{4\sqrt{1785}}{-84}
=\frac{\sqrt{1785}}{-21}
$